{"id":4413,"date":"2019-06-16T15:54:42","date_gmt":"2019-06-16T15:54:42","guid":{"rendered":"https:\/\/www.math.columbia.edu\/~dejong\/wordpress\/?p=4413"},"modified":"2019-06-16T15:54:42","modified_gmt":"2019-06-16T15:54:42","slug":"cohomology-and-motives","status":"publish","type":"post","link":"https:\/\/www.math.columbia.edu\/~dejong\/wordpress\/?p=4413","title":{"rendered":"Cohomology and motives"},"content":{"rendered":"<p>This summer I am trying to write a little bit about Weil cohomology theories for the Stacks project. My motivation is that I want to add the theorem that over a field of characteristic zero de Rham cohomology is one. And in turn, I became motivated to do this, because of the discussions I had with our graduate students in my course <a href=\"https:\/\/www.math.columbia.edu\/~dejong\/wordpress\/?p=4392\">Ask me anything<\/a>. Because after all: what is a &#8220;good cohomology theory&#8221; for algebraic varieties?<\/p>\n<p>While working on this, I found that I had never properly understood the reason for all the conditions imposed by Kleiman in his paper. I still haven&#8217;t understood, I think. In this post I will discuss a basic question I had as I worked through this material and the answers I came up with so far.<\/p>\n<p>Let k be an algebraically closed field; this will be the base field for our smooth projective varieties X, Y, Z. Let F be a field of characteristic 0; this will be the coefficient field for our cohomologies. Feel free to assume F is algebraically closed too. A Weil cohomology theory H^* assigns a graded commutative F-algebra H^*(X) to X in a contravariant manner. It comes with additional structure, namely trace maps and cycle classes, and it has to satisfy a bunch of axioms:<\/p>\n<p>(A) Poincare duality: if dim(X) = d the trace map H^{2d}(X)(d) &#8212;> F is an isomorphism, H^i nonzero only for 0 &le; i &le; 2d, H^i is finite dimensional and the pairing H^i(X) x H^{2d &#8211; i}(X)(d) &#8212;> F defined using cup product and the trace map is nondegenerate,<\/p>\n<p>(B) Kunneth formula: H^*(X x Y) = &bigoplus; H^i(X) &otimes; H^j(Y) and this is compatible with trace maps.<\/p>\n<p>(C) Cycle classes are compatible with pullbacks, pushforwards, intersection products, and trace of the cycle class of a point on Spec(k) is 1.<\/p>\n<p>Remark 1: I&#8217;ve written the axioms slightly differently from Kleiman in his paper &#8220;Algebraic cycles and the Weil conjecture&#8221;. In particular I am keeping track of Tate twists and I am adding the axiom that trace is compatible with Kunneth (which you can deduce from the other axioms &#8212; but will become important later).<\/p>\n<p>Remark 2: In some references compatibility of cycle classes and pushforwards is omitted. But without this compatibility I immediately get stuck, for example I don&#8217;t know how to compute the class of the diagonal without this axiom. If you know a proof of this compatibility from the other axioms, please drop me an email.<\/p>\n<p>Let M_k be the symmetric monoidal category of Chow motives over k (using rational equivalence). Let h(X) be the motive of X and recall that h(-) is contravariant. Let us write 1(1) for the Tate motive, i.e., the inverse of the invertible object h^2(P^1) of M_k.<\/p>\n<p>A key consequence of the axioms (A, (B), (C) is that H^*(X) = G(h(X)) for some symmetric monoidal functor G from M_k to the symmetric monoidal category of graded F-vector spaces such that G(1(1)) is nonzero only in degree -2.<\/p>\n<p>In fact, let&#8217;s start with a G as above and consider the contravariant functor H^*(X) = G(h(X)) from smooth projective varieties to graded F-vector spaces. What can we say about H^*? It turns out that you get cup products, trace maps, cycles classes and all the axioms (A), (B), (C) as formulated above except for possibly &#8220;the trace map &#8230; isomorphism&#8221; and &#8220;H^i nonzero only for 0 &le; i &le; 2d&#8221;.<\/p>\n<p><strong>Question:<\/strong> Can we make an example of a G where the corresponding H^*(X) does <strong>not<\/strong> have the &#8220;correct&#8221; betti numbers?<\/p>\n<p>For example, we can ask whether there could be a G such that H^*(X) is nonzero in negative degrees for some X? Or we could ask whether we can find a G such that H^0(X) has dimension > 1. I think the answer is &#8220;yes&#8221; when k is the complex numbers and conjecturally &#8220;no&#8221; when the ground field k is the algebraic closure of a finite field.<\/p>\n<p>Remark 3: When k is the algebraic closure of a finite field, a paper of Katz and Messing proves the betti numbers are the same for any Weil cohomology theory satisfying more axioms (namely some Lefschetz type thing). As far as I can tell, this result doesn&#8217;t apply to answer my question above, since I&#8217;m even weakening the assumptions of a Weil cohomology theory.<\/p>\n<p>Construction of a weird G when both k and F are the field of complex numbers. Namely, let (H&#8217;)^* be the functor which sends X to (H&#8217;)^*(X) = &bigoplus; H^{p, q}(X) viewed as a bigraded vector space over F. This is a Weil cohomology theory: by Hodge theory it is just the same as sending X to its usual cohomology with complex coefficients. By the discussion above we get G&#8217; such that for every motive M we have a bigrading G'(M) = &bigoplus; (G&#8217;)^{p, q}(M). (One could say that the target category is the category of graded complex Hodge structures, suitably defined as a symmetric monoidal category.) Of course as a graded F-vector space we have that the degree of the summand (G&#8217;)^{p, q}(X) is p + q, in other words, we have<\/p>\n<blockquote><p>(G&#8217;)<sup>n<\/sup>(M) = &bigoplus;<sub> n = p + q<\/sub> (G&#8217;)<sup>p, q<\/sup>(M)<\/p><\/blockquote>\n<p>Now I am going to define a weird G by setting G(M) equal to the graded F-vector space with degree n part equal to<\/p>\n<blockquote><p>G<sup>n<\/sup>(M) = &bigoplus;<sub> n = 3p &#8211; q<\/sub> (G&#8217;)<sup>p, q<\/sup>(M)<\/p><\/blockquote>\n<p>Observe that G(1(1)) is still in degree -2! (A technical point is that because I chose 3 and -1 odd the functor G is still compatible with the commutativity constraints which you have to check in order to see that G is a symmetric monoidal functor.) Now, if E is an elliptic curve then H^*(E) = G(h(E)) has betti numbers dim H^{-1}(E) = 1, dim H^0(E) = 1, dim H^1(E) = 0, dim H^2(E) = 1, dim H^3(E) = 1 and everything else zero. Cool!<\/p>\n<p>On the other hand, let p be a prime number and suppose that k is the algebraic closure of the field with p elements. Then I think conjecturally all objects in M_k &otimes; F are semi-simple and all simple objects are &#8220;1 dimensional&#8221;. Moreover, I think that those simple guys are classified by Weil p-numbers &alpha; in F up to multiplication by roots of unity (these &alpha; are algebraic numbers, but aren&#8217;t necessarily algebraic integers, and have a weight which is an integer which can be negative). Say M(&alpha;) is the motive corresponding to &alpha;. Now the point is that given an &alpha; of weight zero, its nth root for any n > 1 is also a Weil p-number of weight zero. Thus the 1-dimensional F-vector space G(M(&alpha;)) had better be in degree 0. And this then fixes the degrees for all motives because the motive corresponding to &alpha; = p^{-1} is 1(1) which we are requiring to be in degree -2.<\/p>\n<p>Enjoy!<\/p>\n","protected":false},"excerpt":{"rendered":"<p>This summer I am trying to write a little bit about Weil cohomology theories for the Stacks project. My motivation is that I want to add the theorem that over a field of characteristic zero de Rham cohomology is one. &hellip; <a href=\"https:\/\/www.math.columbia.edu\/~dejong\/wordpress\/?p=4413\">Continue reading <span class=\"meta-nav\">&rarr;<\/span><\/a><\/p>\n","protected":false},"author":2,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[1],"tags":[],"class_list":["post-4413","post","type-post","status-publish","format-standard","hentry","category-uncategorized"],"_links":{"self":[{"href":"https:\/\/www.math.columbia.edu\/~dejong\/wordpress\/index.php?rest_route=\/wp\/v2\/posts\/4413","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.math.columbia.edu\/~dejong\/wordpress\/index.php?rest_route=\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.math.columbia.edu\/~dejong\/wordpress\/index.php?rest_route=\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.math.columbia.edu\/~dejong\/wordpress\/index.php?rest_route=\/wp\/v2\/users\/2"}],"replies":[{"embeddable":true,"href":"https:\/\/www.math.columbia.edu\/~dejong\/wordpress\/index.php?rest_route=%2Fwp%2Fv2%2Fcomments&post=4413"}],"version-history":[{"count":14,"href":"https:\/\/www.math.columbia.edu\/~dejong\/wordpress\/index.php?rest_route=\/wp\/v2\/posts\/4413\/revisions"}],"predecessor-version":[{"id":4427,"href":"https:\/\/www.math.columbia.edu\/~dejong\/wordpress\/index.php?rest_route=\/wp\/v2\/posts\/4413\/revisions\/4427"}],"wp:attachment":[{"href":"https:\/\/www.math.columbia.edu\/~dejong\/wordpress\/index.php?rest_route=%2Fwp%2Fv2%2Fmedia&parent=4413"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.math.columbia.edu\/~dejong\/wordpress\/index.php?rest_route=%2Fwp%2Fv2%2Fcategories&post=4413"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.math.columbia.edu\/~dejong\/wordpress\/index.php?rest_route=%2Fwp%2Fv2%2Ftags&post=4413"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}